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jmc

algebra junior

Problem

The admission fee for an exhibition is \25 \ per child. Last Tuesday, the exhibition collected \1950 1$?
Solution
Let be the number of adults and be the number of children. Then we have Rearranging terms gives us Since the number of adults must be an integer, this tells us that is a multiple of 25.

The ratio we want close to 1 is If , then , which means that . In other words, .

The multiple of 25 that comes closest to this is 50, and hence must be 50. Then, . So the ratio of adults to children closest to 1 is
Final answer
\frac{27}{25}