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Question

Let w, x, y, and z be whole numbers. If 2^w 3^x 5^y 7^z = 588, then what does 2w + 3x + 5y + 7z equal?

Accepted Answer

The prime factorization of 588 is 2^237^2. We can see w=2, x=1, and z=2. Because 5^0=1, y=0. 2w+3x+5y+7z=4+3+0+14=21