Browse · MATH Print → jmc algebra intermediate Problem Compute ⌊2006!+2005!2007!+2004!⌋.(Note that ⌊x⌋ denotes the greatest integer less than or equal to x.) Solution — click to reveal We have ⌊2006!+2005!2007!+2004!⌋=⌊(2006+1)⋅2005!(2007⋅2006+20051)⋅2005!⌋=⌊20072007⋅2006+20051⌋=⌊2006+2005⋅20071⌋=2006. Final answer 2006 ← Previous problem Next problem →