Browse · MATH Print → jmc algebra intermediate Problem The expression 16x2−106x−105 can be written as (8x+a)(2x+b), where a and b are integers. What is a+2b? Solution — click to reveal We see that 16x2−106x−105=(8x+7)(2x−15), thus a=7 and b=−15 and a+2b=−23. Final answer -23 ← Previous problem Next problem →