jmc

Clearly, $$.4<.48017<.5$$ Since the function $f(x)=x^3$ is strictly increasing, we can say that $$.4^3<.48017^3<.5^3$$ from which it follows that $\text{A}$ is much too small and $\text{C}$ is much too large, so $\boxed{0.110}$ is the answer.