Browse · MATH Print → jmc algebra intermediate Problem Part of the graph of f(x)=ax3+bx2+cx+d is shown. What is b? Solution — click to reveal We have 0=f(−1)=−a+b−c+dand 0=f(1)=a+b+c+d,so b+d=0. Also d=f(0)=2, so b=−2. Final answer -2 ← Previous problem Next problem →
