align* 97 53 &= .9 10.7 10 53 &= .9.7 53 .9.7 53 align*

jmc

prealgebra junior

Problem

\frac{9}{7 \times 53} =

(A)

\frac{.9}{.7 \times 53}

(B)

\frac{.9}{.7 \times .53}

(C)

\frac{.9}{.7 \times 5.3}

(D)

\frac{.9}{7 \times .53}

Solution

\frac{9}{7 \times 53} = \frac{.9 \times 10}{.7 \times 10 \times 53} = \frac{.9}{.7 \times 53} \to \frac{.9}{.7 \times 53}

Final answer