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jmc

prealgebra intermediate

Problem

What is the least four-digit positive integer, with all different digits, that is divisible by each of its digits?
Solution
Since the problem asks for the least possible number, you should start with the lowest number () and work your way up (and across the number.) Nothing is divisible by zero, so zero cannot be one of the digits in the four-digit number. Every whole number is divisible by , so the digit should be in the thousands place to create the smallest number. The digits must be different, so put a in the hundreds place. Now, you have to make sure the number is even. You can put a in the tens place, but you cannot use for the ones place since is not divisible by or . is not even, so it is not divisible by (or for that matter, by ). is divisible by all of its own digits.
Final answer
1236