Browse · MATH Print → jmc algebra intermediate Problem Find the fifth term of the geometric sequence with first term 2 and second term 41. Solution — click to reveal The common ratio is 241=81, so the kth term is 2⋅(81)k−1. Thus we have:2⋅(81)4=2122=2111=20481. Final answer \frac{1}{2048} ← Previous problem Next problem →