Browse · MATH Print → jmc algebra intermediate Problem Given that 3x2−2(x2+4)=42, what is the value of x4? Solution — click to reveal Begin by simplifying the left side: 3x2−2x2−8=42 We can combine terms and solve for x2: 3x2−2x2⇒x2=42+8=50 Squaring both sides, we find: (x2)2⇒x4=502=2500 Final answer 2500 ← Previous problem Next problem →