Browse · MATH Print → jmc algebra intermediate Problem If (x+y)2=45 and xy=10, what is (x−y)2? Solution — click to reveal We know that (x+y)2=x2+2xy+y2 and (x−y)2=x2−2xy+y2. We can see that (x−y)2=(x2+2xy+y2)−4xy=(x+y)2−4xy=45−40=5. Final answer 5 ← Previous problem Next problem →