What is the value of log104+2log105+3log102+6log105+log108?
Solution — click to reveal
We use the two identities alogbx=logbxa and logbx+logby=logbxy. The given expression becomes log104+2log105+3log102+6log105+log108=log1022+log1052+log1023+log1056+log1023=log10(22⋅52⋅23⋅56⋅23)=log10(28⋅58)=log10108=8.