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jmc

algebra intermediate

Problem

Solve for

x

:

2^{x - 3} = 4^{x + 1}

Solution

2^{x - 3} 2^{x - 3} 2^{x - 3} x - 3 x = 4^{x + 1} = (2^{2})^{x + 1} = 2^{2 x + 2} = 2 x + 2 = - 5

Final answer

-5