jmc

Since $f(x)$ is an odd function, $f(-x)=-f(x).$ In particular, $$f(3)=-f(-3)=-5.$$Therefore, the graph of $f(x)$ must also pass through the point $\boxed{(3,-5)}.$

Also, $$f(0)=-f(0),$$so $f(0)=0.$ Thus, $\boxed{(0,0)}$ is also an acceptable answer. (This is assuming that $f(x)$ is defined at $x=0.$)