Browse · MATH Print → jmc algebra intermediate Problem Simplify (5−3i)(−4+3i). Solution — click to reveal (5−3i)(−4+3i)=5(−4)+5(3i)−3i(−4)−3i(3i)=−20+15i+12i+9=−11+27i. Final answer -11 + 27i ← Previous problem Next problem →