Browse · MATH Print → jmc algebra intermediate Problem Let a, b, c be positive real numbers. Find the minimum value of abc(a+b)(a+c)(b+c). Solution — click to reveal By AM-GM, a+b≥2ab,a+c≥2ac,b+c≥2bc,so abc(a+b)(a+c)(b+c)≥abc2ab⋅2ac⋅2bc=8.Equality occurs when a=b=c, so the minimum value is 8. Final answer 8 ← Previous problem Next problem →