jmc

Terminating decimals can be expressed as $\frac{a}{10^b}$. So, we try to get our fraction in this form: $$\frac{11}{125}=\frac{11}{5^3}=\frac{11}{5^3}\cdot \frac{2^3}{2^3}=\frac{11\cdot 2^3}{10^3}=\frac{88}{1000}=\boxed{0.088}.$$