jmc

If the coordinates of point $A$ are $(x,y)$ then $x$ and $y$ must satisfy the equations of both lines (as $A$ is on both lines). Substituting the first equation into the second gives: $$\begin{array}{rl}2x+5y& =11\\ 6y+5y& =11\\ 11y& =11\\ y& =1.\end{array}$$So now $x=3y=3$, and so the coordinates of point $A$ are $(3,1)$. The sum of these is $3+1=\boxed{4}$.