Browse · MathNet Print → Ukrainian Mathematical Olympiad Ukraine geometry Problem Prove that for any real numbers x and y, both taken on the segment [0;2π], the inequality cosx+cosy+∣cos(x+y)∣≥1 holds. Solution — click to reveal Для x,y∈[0;π/2] маємо: cosx+cosy+∣cos(x+y)∣≥cosxsiny+cosysinx+cos2(x+y)==sin(x+y)+cos2(x+y)≥sin2(x+y)+cos2(x+y)=1. Techniques Trigonometry ← Previous problem Next problem →