jmc

Using angle chasing is a good way to solve this problem. $BD=DC$, so $\angle DBC=\angle DCB=70$, because it is an isosceles triangle. Then $\angle CDB=180-(70+70)=40$. Since $\angle ADB$ and $\angle BDC$ are supplementary, $\angle ADB=180-40=\boxed{140}$.