Browse · MATH Print → jmc algebra intermediate Problem Real numbers x and y have an arithmetic mean of 18 and a geometric mean of 92. Find x2+y2. Solution — click to reveal The givens tell us that 2x+y=18 and xy=92, or x+y=36 and xy=92. (x+y)2=x2+2xy+y2, so x2+y2=(x+y)2−2xy=362−2⋅92=1296−184=1112 Final answer 1112 ← Previous problem Next problem →