Browse · harp Print → smc number theory intermediate Problem The number of digits in the number N=212×58 is (A) 9 (B) 10 (C) 11 (D) 12 Solution — click to reveal N=212⋅58=24⋅28⋅58=24⋅(2⋅5)8=24⋅108=16⋅100000000, which has 2+8=10 digits, so the answer is 10. Final answer B ← Previous problem Next problem →