Firstly, 3(6-12)=18-1-12=17-12. Because 012<1, we have 17-12=17.

jmc

algebra intermediate

Problem

Evaluate

⌈ 3 (6 - \frac{1}{2}) ⌉

Solution

Firstly,

3 (6 - \frac{1}{2}) = 18 - 1 - \frac{1}{2} = 17 - \frac{1}{2}

. Because

0 \leq \frac{1}{2} < 1

, we have

⌈ 17 - \frac{1}{2} ⌉ = 17

Final answer