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PrintSAUDI ARABIAN IMO Booklet 2023
Saudi Arabia 2023 counting and probability
Problem
On a line, 200 points are marked and numbered from left to right. Various crickets jump around the line. Each starts at point , jumping on the marked points and ending up at point . In addition, each cricket jumps from a marked point to another marked point with a greater number. When all the crickets have finished jumping, it turns out that for every pair with , there was a cricket that jumped directly from point to point , without visiting any of the points in between the two. Show that the number of crickets was at least and that there is a way that crickets could jump satisfying the conditions above.
Solution
For every pair where and there is a cricket that jumped from to and no cricket can do two such jumps. Therefore there are at least crickets.
Consider the following paths of crickets:
1. ; 2. where , 3. , where , 4. , where and .
Counting the different paths above from each type, there are such paths, and one can check that for every pair of marked points there is a cricket doing the jump between the points.
Consider the following paths of crickets:
1. ; 2. where , 3. , where , 4. , where and .
Counting the different paths above from each type, there are such paths, and one can check that for every pair of marked points there is a cricket doing the jump between the points.
Final answer
10000
Techniques
Pigeonhole principleEnumeration with symmetry