The expression inside the ceiling function evaluates to (74)^2=4916=3+116 Because 0116<1, we have (74)^2 = 3 + 116 = 4.

jmc

algebra intermediate

Problem

Evaluate

⌈ (\frac{7}{4})^{2} ⌉

Solution

The expression inside the ceiling function evaluates to

(\frac{7}{4})^{2} = \frac{49}{16} = 3 + \frac{1}{16}

Because

0 \leq \frac{1}{16} < 1

, we have

⌈ (\frac{7}{4})^{2} ⌉ = ⌈ 3 + \frac{1}{16} ⌉ = 4 .

Final answer