imc

Using factoring: $2x^2+3x-5=0$ $(2x+5)(x-1)=0$ $x=-\frac{5}{2}$ or $x=1$ So $d$ and $e$ are $-\frac{5}{2}$ and $1$. Therefore the answer is $\left(-\frac{5}{2}-1\right)(1-1)=\left(-\frac{7}{2}\right)(0)=\boxed{0}$