Browse · MathNet
PrintMongolian National Mathematical Olympiad
Mongolia geometry
Problem
Two circles and intersected at points and . Line through is intersect the at point and intersect the at point . The line intersect the at point different from and the line intersect the at point different from . If is circumcenter of triangle then prove that .
(Proposed by B. Bat-Od)

(Proposed by B. Bat-Od)
Solution
We draw the circumcircle of , and denote . So and from here we get . Other hand , so . From here we have , hence is cyclic. Therefore, from we have . From here we have . We know so .
Techniques
Cyclic quadrilateralsAngle chasing