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imc

geometry intermediate

Problem

In rectangle , we have , , , for some integer . What is the area of rectangle ?
(A)
(B)
(C)
(D)
(E)
Solution
This solution is the same as Solution 1 up to the point where we find that . We build right triangles so we can use the Pythagorean Theorem. The triangle with hypotenuse has legs and , while the triangle with hypotenuse has legs and . Aha! The two triangles are similar by SAS, with one triangle having side lengths times the other! Let . Then from our reasoning above, we have . Finally, the area of the rectangle is .
Final answer
E