Browse · MATH Print → jmc algebra junior Problem Evaluate 312×320×315×360. Solution — click to reveal We have 312×320×315×360=322⋅31×322⋅51×331⋅51×322⋅31⋅51=3(22⋅31)(22⋅51)(31⋅51)(22⋅31⋅51)=3(22⋅22⋅22)(31⋅31⋅31)(51⋅51⋅51)=3(26)(33)(53)=326×333×353=(22)(3)(5)=60. Final answer 60 ← Previous problem Next problem →