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Belarus geometry
Problem
Points and are marked on the half-hyperbola which lies in the first quadrant of the Cartesian plane. The abscissa of is greater than the abscissa of . Let be the intersection point of the other half-hyperbola and the line passing through the origin and .
Prove that the angle is equal to one of the angles between the line and the tangent to the hyperbola at point .

Prove that the angle is equal to one of the angles between the line and the tangent to the hyperbola at point .
Solution
Let be tangent to the hyperbola at point , be the intersection of -axis and , be the intersection point of the -axis and ,
be the intersection point of and the line through parallel to -axis (see the Fig.). Since and are symmetric with respect to the origin, we see that . Further,
On the other hand, , i.e.
Further, and Hence .
So,
as required.
be the intersection point of and the line through parallel to -axis (see the Fig.). Since and are symmetric with respect to the origin, we see that . Further,
On the other hand, , i.e.
Further, and Hence .
So,
as required.
Techniques
Cartesian coordinatesTrigonometryRotationAngle chasing