align* 210+4100+61000 &= 2001000+401000+61000 &= 2461000 &= .246 .246 align*

jmc

prealgebra junior

Problem

\frac{2}{10} + \frac{4}{100} + \frac{6}{1000} =

(A)

.012

(B)

.0246

(C)

.12

(D)

.246

Solution

\frac{2}{10} + \frac{4}{100} + \frac{6}{1000} = \frac{200}{1000} + \frac{40}{1000} + \frac{6}{1000} = \frac{246}{1000} = .246 \to .246

Final answer