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algebra intermediate
Problem
For every triple of non-zero real numbers, form the number . The set of all numbers formed is
(A)
(B)
(C)
(D)
Solution
or depending whether is positive or negative. If , , and are positive, then the entire thing amounts to . If one of the three is negative and the other two positive, the answer is . If two of the three is negative and one is positive, the answer is . If all three are negative, the answer is . Therefore the set is .
Final answer
B