Browse · MATH Print → jmc number theory junior Problem What is the sum of the reciprocals of the natural-number factors of 6? Solution — click to reveal The natural-number factors of 6 are 1, 6, 2, 3. The sum of their reciprocals is 1/1+1/6+1/2+1/3=6/6+1/6+3/6+2/6=12/6=2. Final answer 2 ← Previous problem Next problem →