Let x, y, z be positive real numbers. Prove that x2+y2+2z2xy+y2+z2+2x2yz+z2+x2+2y2zx≤23.
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We have x2+y2+2z2xy+y2+z2+2x2yz+z2+x2+2y2zx≤xy+yz+zx+z2xy+xy+yz+zx+x2yz+xy+yz+zx+y2zx=(z+x)(y+z)xy+(x+y)(z+x)yz+(y+z)(x+y)zx≤2z+xx+y+zy+2x+yy+z+xz+2y+zz+x+yx=2x+yx+y+y+zy+z+z+xz+x=23. Equality holds if and only if x=y=z.