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jmc

geometry senior

Problem

Five points , , , , and lie on a flat field. is directly north of , is directly west of , is directly south of , and is directly east of . The distance between and is 140 m. A hot-air balloon is positioned in the air at directly above . The balloon is held in place by four ropes , , , and . Rope has length 150 m and rope has length 130 m.
problem


To reduce the total length of rope used, rope and rope are to be replaced by a single rope where is a point on the straight line between and . (The balloon remains at the same position above as described above.) Determine the greatest length of rope that can be saved.
Solution
To save the most rope, we must have having minimum length. For to have minimum length, must be perpendicular to . (Among other things, we can see from this diagram that sliding away from the perpendicular position does make longer.) In the diagram, , and . Let and . Then . By the Pythagorean Theorem in , . By the Pythagorean Theorem in , . Subtracting the second equation from the first, we obtain Therefore, or so . So the shortest possible rope that we can use is 120 m, which saves m of rope.
Final answer
160