Browse · MATH Print → jmc algebra intermediate Problem Simplify −3(1+4i)+i(−2−i). Solution — click to reveal −3(1+4i)+i(−2−i)=−3−12i−2i−i2=−3−12i−2i+1=−2−14i=−2−14i. Final answer -2-14i ← Previous problem Next problem →