Browse · MATH Print → jmc prealgebra intermediate Problem What is the greatest common divisor of 1313 and 1001? Solution — click to reveal We start by finding the prime factorizations of 1313 and 1001. We have 1313=1300+13=13(100+1)=13⋅101 and 1001=7⋅143=7⋅11⋅13. Therefore, gcd(1313,1001)=13. Final answer 13 ← Previous problem Next problem →