Browse · MATH Print → jmc algebra intermediate Problem For some positive integers m and n, 23+28+23−28=m+n.Enter the ordered pair (m,n). Solution — click to reveal Let x=23+28+23−28. Then x2=23+28+223+2823−28+23−28=46+2232−28=46+2501=46+2004.Hence, (m,n)=(46,2004). Final answer (46,2004) ← Previous problem Next problem →