Simplify 7 2 2^3 7^3.

We have: 7 2 2^3 7^3=2^4 7^4=14^4=14^2=196.

jmc

prealgebra intermediate

Problem

Simplify

7 \cdot 2 \cdot 2^{3} \cdot 7^{3}

Solution

We have:

7 \cdot 2 \cdot 2^{3} \cdot 7^{3} = 2^{4} \cdot 7^{4} = 1 4^{4} = 1 4^{2} = 196

Final answer

196