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smc

geometry senior

Problem

In triangle , inches, inches, inches. The radius of the inscribed circle is:
(A)
(B)
(C)
(D)
Solution
The inradius is equal to the area divided by semiperimeter. The area is because it's a right triangle, as it's side length satisfies the Pythagorean Theorem. The semiperimeter is . Therefore the inradius is .
Final answer
B