Browse · MATH Print → jmc algebra intermediate Problem What is the value of x in the equation 1616+1616+1616+1616=2x? Solution — click to reveal We rewrite the left side 1616+1616+1616+1616 as 4⋅1616=22⋅(24)16=22⋅264=266. We have 266=2x, so the value of x is 66. Final answer 66 ← Previous problem Next problem →