jmc

$$\begin{array}{cccccc}\text{multicolumn}2r2x^2& -3x& -11& & & \\ \text{cline}2-6x^2+7x-5& 2x^4& +11x^3& -42x^2& -60x& +47\\ \text{multicolumn}2r-2x^4& -14x^3& +10x^2& & & \\ \text{cline}2-4\text{multicolumn}2r0& -3x^3& -32x^2& -60x& & \\ \text{multicolumn}2r& +3x^3& +21x^2& -15x& & \\ \text{cline}3-5\text{multicolumn}2r& 0& -11x^2& -75x& +47& \\ \text{multicolumn}2r& & +11x^2& +77x& -55& \\ \text{cline}4-6\text{multicolumn}2r& & 0& 2x& -8& \end{array}$$Since the degree of $2x-8$ is lower than that of $x^2+7x-5$, we cannot divide any further. So our remainder is $\boxed{2x-8}$.