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Croatian Mathematical Olympiad

Croatia geometry

Problem

Let be a positive integer. Points are located on the inside of a circle, and points are on the circle, so that the lines , , \dots, are mutually disjoint. A grasshopper can jump from point to point (for ) if and only if the line does not go through any of the inner points of the lines .

Show that the grasshopper can take a series of jumps to get from any point to any point . (Russia 1994)
Solution
Let a path be any line and a wall be any line . We say that a path and a wall intersect if the path goes through an inner point of the wall. A path is good if there is no wall to intersect it, and a wall is irrelevant if it does not intersect any path.

Claim 1. For any there exists at least one good path from point .

Proof. We will prove the claim for point , and it holds analogously for all points . Define the distance between a point and a wall as Since all walls are mutually disjoint, we know that none of the walls contain point . Let be the wall closest to . We claim that the path is good. If we assume the contrary, that means that there exists a wall which intersects , but then this wall is closer to than wall , which is a contradiction.

Claim 2. There exists at least one irrelevant wall.

Proof. Without loss of generality, we can assume that points are the vertices of the convex hull of , and that they are labelled clockwise in that order as the vertices of polygon . If the wall is irrelevant, we are done. Therefore, assume that intersects some path. That means that this wall goes through the inner points of polygon , and since the walls are mutually disjoint, we conclude that must also intersect a path which is the side of , because it cannot pass through any of the vertices of except . Let be the intersection of wall and a side of . Consider the arc (clockwise from point to point ), and note that it contains points . We can repeat this inference for wall . Since all walls are mutually disjoint, its corresponding arc is strictly smaller than the arc of . Therefore, if all of the walls are relevant, then wall must surely be irrelevant.

Finally, we prove the problem statement by mathematical induction on . The claim obviously holds for . Assume the claim holds for some positive integer . For it follows from Claim 2 that there exists a point such that the wall is irrelevant. By the inductive assumption, we can conclude that the claim holds for all points except possibly point . However, by Claim 1, point is connected by a good path with at least one of the remaining points, which proves the claim for .

Techniques

Convex hullsDistance chasing