Browse · MATH Print → jmc counting and probability junior Problem Compute (715). You are told that (814)=3003 and (714)=3432. Solution — click to reveal By Pascal's Rule, (715)(715)(715)(715)(715)=(614)+(714)=(14−614)+(714)=(814)+(714)=3003+3432=6435 Final answer 6435 ← Previous problem Next problem →