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Print65th Czech and Slovak Mathematical Olympiad
Czech Republic counting and probability
Problem
Mathematics clubs are very popular in a certain city. Any two of them have at least one common member. Prove that one can distribute rulers and compasses to the citizens in such a way that only one citizen gets both (compass and ruler) and any club has at its disposal both, compass and ruler, from its members.
Solution
Let us consider the club with the least number of its members (in case there is more such clubs, we take any). We give to one of its members (let us call him Jacob) both a compass and a ruler. Each of the other members of the club will get a compass. Any other citizen will get a ruler. We show that this distribution complies with the conditions of the problem:
Any club which has Jacob as its member has certainly both instruments.
If there is a club where Jacob does not belong, then it has at least one common member with the club , that is, there is at least a compass at disposal in the club. If there were no ruler in the club, it would mean that it is a “subclub” of and therefore has at least one member (Jacob) less than , which is a contradiction with the choice of . The described distribution really satisfies the conditions of the problem.
Any club which has Jacob as its member has certainly both instruments.
If there is a club where Jacob does not belong, then it has at least one common member with the club , that is, there is at least a compass at disposal in the club. If there were no ruler in the club, it would mean that it is a “subclub” of and therefore has at least one member (Jacob) less than , which is a contradiction with the choice of . The described distribution really satisfies the conditions of the problem.
Techniques
Coloring schemes, extremal arguments