Browse · MATH Print → jmc algebra intermediate Problem Simplify (3−2i)2. (Your answer should be of the form a+bi.) Solution — click to reveal (3−2i)2=(3−2i)(3−2i)=3(3)+3(−2i)−2i(3)−2i(−2i)=9−6i−6i−4=5−12i. Final answer 5-12i ← Previous problem Next problem →