jmc

We drop an altitude from either vertex of the shorter base, forming a right triangle with hypotenuse of length 10 and one leg of length $(16-4)/2=6$. The remaining leg, which is the height of the trapezoid, is thus 8.

Therefore, the area of the trapezoid is $\frac{4+16}{2}\cdot 8=\boxed{80}$ square centimeters.