smc

Substitute $y$ into the other equation. $$2\log x=\log 2x$$ Using a logarithm property, $$2\log x=\log 2+\log x$$ Subtract both sides by $\log x$ to get $$\log x=\log 2$$ Thus, $x=2$. Since both $2\log x$ and $\log 2x$ are functions, there is only one corresponding y-value, so the answer is $\boxed{\text{They intersect at 1 point only}}$.