imc

The product will be even if at least one selected number is even, and odd if none are. Using complementary counting, the chance that both numbers are odd is $\frac{\left(\genfrac{}{}{0ex}{}{3}{2}\right)}{\left(\genfrac{}{}{0ex}{}{5}{2}\right)}=\frac{3}{10}$, so the answer is $1-0.3$ which is $\boxed{\text{(D) }0.7}$. An alternate way to finish: Since it is odd if none are even, the probability is $1-(\frac{3}{5}\cdot \frac{2}{4})=1-\frac{3}{10}=0.7⟹\boxed{0.7}$.