imc

Notice that, for $n\ge 2$, $2015^n\equiv 15^n$ is congruent to $25(\mathrm{mod}100)$ when $n$ is even and $75(\mathrm{mod}100)$ when $n$ is odd. (Check for yourself). Since $2016$ is even, $2015^{2016}\equiv 25(\mathrm{mod}100)$ and $2015^{2016}-2017\equiv 25-17\equiv \underline{0}8(\mathrm{mod}100)$. So the answer is $\text{(A)}\boxed{0}$.